Question

2/3×2log64-1/2×2log16

Answer 1

`(2)/(3) *2log 64 - (1)/(2) *2log 16`


`(2)/(3) *2log \ 2^6 - (1)/(3) *2 \ log \ 2^4`


`(2)/(3) *(6)*2log2 - (1)/(2) *(4)*2log2`


`4*(1) - 2*(1)`


`= 2`