Question

If you begin with 1250 grams of N2 and 225 grams of H2 in the reaction that forms ammonia gas (NH3), how much ammonia will be formed? What is the limiting reagent? How much of the reagent is left when the maximum amount of ammonia is formed?

(AP Chemistry summer homework packet)


Please help! Thanks. :)

Answer 1

N₂+3H₂⇒ 2NH₃
m(NH₃)=1250+225*2=1700 grams
N₂ is the limiting reagent.
1250 grams are left when the maximum amount of ammonia is formed.