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Inverse of y=x^2 -10x 27

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y= x^(2) -10x+27 \\ y-2= x^(2) -10x+27-2 \\ y-2= x^(2) -10x+25 \\ y-2= (x-5)^(2) \\ x-5= √(y-2) \\ x=5+ √(y-2)

Therefore, the inverse 0f y = x^2 - 10x + 27 is
y = 5+ √(y-2)
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User Antony Delaney
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