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What are the possible number of negative zeros of f(x) = -2x7 - 2x6 7x5 - 7x4 4x3 4x2 ?

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User Salwa
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1 Answer

5 votes
Hello,

f(-x)=2x^7-2x^6-7x^5-7x^4-4x^3+4x^2 has 2 changing signes.

Maximum possible number of negative roots is 2


answered
User TiansHUo
by
7.8k points
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