Question

Find −3a2 − b3 + 3c2 − 2b3 if a = 2, b = −1, and c = 3

Answer 1

-3(2)2-(-1)3+3(3)2-2(-1)3. FIRST SUBSTITUTE ALL GIVEN VALUES -12+3+18+6. SIMPLIFICATION 15. ANSWER (just remember -×- =+ )

Answer 2

a = 2, b = -1, c = 3

-3a^2 - b^3 + 3c^2 - 2b^3
-3(2^2) - (-1^3) + 3(3^2) - 2(-1^3)
-3(4) - (-1) + 3(9) - 2(-1)
-12 + 1 + 27 + 2
-12 + 30
18 <===