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Find the first derivative of y = sin^2(cos2x)

asked
User Nirav D
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1 Answer

4 votes
Hello,

y=sin²(cos(2x))
y'=2*sin(cos(2x))*cos(cos(2x))*(-sin(2x)*2)
= -4*sin(cos(2x))*cos(cos(2x))*sin(2x)
answered
User Narmageddon
by
8.4k points

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