Question

an engineer is surveying a building with a device that is 6 feet above the ground. he is 60 feet from the building and is looking with an angle of elevation of 45°. how tall is the building? ... i'm really bad at trig. x....x

Answer 1

The entire system forms a right angle triangle.
Let the height of the bulding be x, then tan 45 = (x - 6)/60
60 = x - 6
x = 60 + 6 = 66

Therefore the height of the building is 66 feet.