Question

A board 109 cm long has to be cut into two pieces so that the longer part is 10 cm more than twice as long as the shorter part. Find the length of each part

Answer 1

x = longer section
y = shorter section

x + y = 109
x = 2y + 10

so we sub in eq 2 into eq 1
2y + 10 + y = 109
3y + 10 = 109
3y = 109 - 10
3y = 99
y = 99/3
y = 33 <=== shorter section is 33 cm

x = 2y + 10
x = 2(33) + 10
x = 66 + 10
x = 76 <=== longer section is 76 cm