Question

Find an equation of the tangent line to the curve at the given point. y=sqrt(x) (1,1)

Answer 1

The tangent line of a curve or a function can be obtained by taking the first derivative of the function given. In this case, the derivative of  y=sqrt(x) is equal to y'  = 0.5 x ^ -0.5. At point (1,1), y' is equal to 0.5. Using point slope form, the equation is y  = 0.5x - 0.5 +1 = 0.5 x + 0.5