asked 82.5k views
5 votes
Let f(x) = 8x3 − 22x2 − 4 and g(x) = 4x − 3. Find f of x over g of x

2 Answers

4 votes
f(x) = 8x³ - 22x² - 4
g(x) = 4x - 3


(f / g)(x) = (8x^(3) - 22x^(2) - 4)/(4x - 3)

(f / g)(x) = (2(4x^(3)) - 2(11x^(2)) - 2(2))/(4x - 3)

(f / g)(x) = (2(4x^(3) - 11x^(2) - 2))/(4x - 3)

answered
User Mavi Domates
by
7.7k points
2 votes

Answer:


(f(x))/(g(x))=(2(4x^3-11x^2-2))/(4x-3)

Explanation:

The given functions are.....


f(x)= 8x^3-22x^2-4\\ \\ g(x)=4x-3

Using the above functions, we will get......


(f(x))/(g(x))\\ \\ =(8x^3-22x^2-4)/(4x-3)\\ \\ =(2((8x^3)/(2)-(22x^2)/(2)-(4)/(2)))/(4x-3)\\ \\ =(2(4x^3-11x^2-2))/(4x-3)

answered
User Kafels
by
7.8k points
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