Find the number of permutations in the word “embarrass”.

Question

asked Sep 27, 2017 226k views

2 Answers

Tarion · Answer 1 · 2017-10-02T01:46:45+0000

Answer:

504.

Explanation:

We are asked to find the number of permutations in the word “embarrass”.

We can see that embarrass has three repeating words that are a, r, s.

The number of permutations of n objects taken r at a time is
n(c,r)=(n!)/((n-r)!) .

n(9,3)=(9!)/((9-3)!)

n(9,3)=(9!)/(6!)

$n(9,3)=(9\cdot 8\cdot 7\cdot 6!)/(6!)$

$n(9,3)=(9\cdot 8\cdot 7)/(1)$

n(9,3)=504

Therefore, the number of permutations in the word "embarrass" is 504.