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What are the solutions to the quadratic equation? x^2=-5x-3

1 Answer

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Hi.... I'll use the Quadratic Formula....


x^(2)=-5x-3\rightarrow x^(2)+5x+3=0\rightarrow x=\frac{-5\pm \sqrt{5^(2)-4* 1*3}}{2* 1}\rightarrow\\ x=(-5\pm√(13))/(2)\rightarrow \boxed{x_(1)=(-5-√(13))/(2)}\quad \text{or}\quad \boxed{x_(2)=(-5+√(13))/(2)}

Thanks....
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User Eastboundr
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