Question

What is the general form of the equation for the given circle centered at o (0,0) (4,5)?

x^2+y^2+x+y-41=0

Answer 1

The general equation of the circle is expressed as (x-h)2 + (y-k)2 = r2 where (h,k) is the center of the circle. we are are given the center of the circle at (0,0) so the expression is simplified to (x)2 + (y)2 = r2. given the other point, r2 is equal to 41. hence the final equation is x2 + y2 = 41