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6|6-4x|=8x+4

Need help solving the equation. I need help checking the extraneous solutions too.

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6|6-4x|=8x+4\\\\Formula\ for\ absolute\ value\\\\ |a|=a,\ for\ a \geq 0\\ or\\|a|=-a,\ for\ a<0\\\\I\\ for\ 6-4x \geq 0\ \ \ --> \ \ -4x \geq -6\ \ -->\ \ \ x \leq (3)/(2)\\\\ 6(6-4x)=8x+4\\ 36-24x=8x+4\ \ |subtract\ 4\\ 32-24x=8x\ \ | add\ 24x\\ 32=32x\ \ | divide\ by\ 32\\ x=1\ \ \ and\ 1 \leq (3)/(2)\\\\ II\\ for\ 6-4x <0\ \ \ --> \ \ -4x < -6\ \ -->\ \ \ x > (3)/(2)\\\\ 6(-6+4x)=8x+4\\ -36+24x=8x+4\ \ | subtract4\\ -40+24x=8x\ \ \ | subtract\ 24x\\ -40=-16x\ \ | divide\ by\ -16
x=2,5\ \ and\ 2,5>(3)/(2)\\\\Solutions:\\ x\in \{1;2,5\}

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