Question

in competition, an athlete threw a flying disk 139 meters through the air. while in flight, the disk traveled at an average speed of 13.0 m/s. how long did the disk remain in the air?

Answer 1

139m/13.0m/s = 10.7sec

Answer 2

Time, t = 10.69 seconds

Step-by-step explanation:

Given that,

Average speed of the disk, v = 13 m/s

The athlete threw a distance through the air, d = 139 meters

We need to find the time the disk remains in the air. Let t is the time taken. The average speed of the disk is given by :

`v=(d)/(t)`

`t=(d)/(v)`

`t=(139\ m)/(13\ m/s)`

t = 10.69 seconds

So, the disk remains in the air for 10.69 seconds. Hence, this is the required solution.