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2 (3e-5f)+3 (e^2+4f) e=3 f=-5

2 (3e-5f)+3 (e^2+4f) e=3 f=-5
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2 (3e-5f)+3 (e^2+4f) e=3 f=-5

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User Soupjake
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8.5k points

1 Answer

1 vote
2(3e - 5f) + 3(e² + 4f)
2[3(3) - 5(-5)] + 3[(3)² + 4(-5)]
2(9 + 25) + 3(9 - 20)
2(34) + 3(-11)
68 - 33
35
answered
User Mike Liddell
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7.9k points
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