Question

how many moles of oxygen are needed to burn 1.33 moles of methyl alcohol (ch3oh)?2ch3oh 3o2 2co2 4h2o

Answer 1

2 CH3OH + 3 O2 = 2 CO2 + 4 H2O

2 moles CH3OH ---------------- 3 moles O2
1.33 moles CH3OH ----------- ( moles O2)

moles O2 = 1.33 x 3 / 2

moles O2 = 3.99 / 2

= 1.995 moles of O2

Answer 2

Answer : The number of moles of oxygen needed to burn are, 1.995 moles

Solution : Given,

Moles of methyl alcohol,
`CH_3OH` = 1.33 mole

The given balanced chemical reaction is,

`2CH_3OH+3O_2\rightarrow 2CO_2+4H_2O`

From the balanced reaction, we conclude that

As, 2 moles of methyl alcohol react with 3 moles of oxygen

So, 1.33 moles of methyl alcohol react with
`(3)/(2)* 1.33=1.995` moles of oxygen

Therefore, the number of moles of oxygen needed to burn are, 1.995 moles