Cos (a-b) - cos (a+b) = 2 sin a sin b

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asked Feb 15, 2017 219k views

1 Answer

Ben Combee · Answer 1 · 2017-02-21T05:26:16+0000

cos(a - b) - cos(a + b) = 2sin(a)sin(b)
[cos(a)cos(b) + sin(a)sin(b)] - [cos(a)cos(b) - sin(a)sin(b)] = 2sin(a)sin(b)
[cos(a)cos(b) - cos(a)cos(b)] + [sin(a)sin(b) + sin(a)sin(b)] = 2sin(a)sin(b)
2sin(a)sin(b) = 2sin(a)sin(b)

Cos (a-b) - cos (a+b) = 2 sin a sin b

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