Question

The amount of heat needed

to raise 2.0 kg of a substance by 80 K is 33 kJ. What is the specific heat of
the substance?

Answer 1

j=joules, c=specific heat, q= energy, and the Tf and Ti are the final and initial temperatures cause I couldn't find a delta sign.


`Q=mc(T_(f)-T_(I)) \\ 33000j=2kg*c*80 \\(33000j)/(2kg*80) =c \\ c=206.25jkg^(-1)`