If 3x^2-2x+7=0, then (x-1/3)^2= ?

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asked Oct 15, 2017 33.6k views

1 Answer

Eskir · Answer 1 · 2017-10-18T22:51:32+0000

3x^2-2x+7=0

3x^2-2x=-7

3(x^2-2/3x)=-7

3(x^2-2/3x+1/9)=-7+3*(1/9)

3(x^2-2/3x+1/9) = -20/3

3(x-1/3)^2 = -20/3

(x-1/3)^2 = (-20/3)/3

(x-1/3)^2 = -20/9

If 3x^2-2x+7=0, then (x-1/3)^2= ?

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