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Select the correct electron configuration for Vanadium. (Atomic Number 23)

1s 2 2s 6 2p 3 3s 2 3p 4 4s 2 3d 5
1s 2 2s 2 2p 6 3s 2 3p 8 4s 2 3d 1
1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 3
1s 2 2s 2 2p 5 3s 2 3p 7 4s 1 3d 4

asked
User Dayanara
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2 Answers

2 votes
1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 3.
answered
User NStal
by
7.9k points
5 votes

Answer : The correct option is,
1s^22s^22p^63s^23p^64s^23d^3

Explanation :

Electronic configuration : It is defined as the distribution or arrangement of electrons of an atom in atomic orbitals.

We are given that the atomic number of vanadium is, 23 that means the number of electrons present in vanadium is, 23.

The electronic configuration of vanadium will be,


1s^22s^22p^63s^23p^64s^23d^3

Hence, the correct option is,
1s^22s^22p^63s^23p^64s^23d^3

answered
User Swordfish
by
8.6k points
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