Question

After 62.0 min, 33.0% of a compound has decomposed. What is the half-life of this reaction assuming first-order kinetics?

Answer 1

Half life is determined using the equation expressed as:

A = Ao e^-kt

First, we need to find for the value k.

A = .67Ao = Ao e^-k(33 min)
k = 0.0121

The half-life is then calculated as follows:
A = .5Ao = Ao e^-0.0121(t)
t = 57.28 min