Question

the pyramid shown has a square base that is 6 feet on each side. it has a surface area of 84 square feet. what is the slant height?

Answer 1

Surface area of a pyramid =
`lw+l \sqrt{ (w^2)/(2)+h^2 } +w \sqrt{ ( l^(2) )/(2) + h^(2) }`

`84=6 * 6 + 6( \sqrt{ (6^2)/(2) +h^2}) +6( \sqrt{ (6^2)/(2) +h^2}) \\ 84=36+12( \sqrt{ (36)/(2) +h^2}) \\ 48=12( √( 18 +h^2)) \\ 4= √(18 +h^2) \\ 16=18 +h^2 \\ h^2=16-18=-2 \\ h= √(-2)`
Which is not real. Hence, the question is not correct.