What is the value of r in this equation for exponential growth? f(x) = 2500({1.75})^(x) ​

Question

What is the value of r in this equation for exponential growth?


`f(x) = 2500({1.75})^(x)`
​

Answer 1

`r=0.75 = 75`%

Explanation:

Equation of General exponential growth function is

`f(x)=a(1+r)^(x)` ------------ (1)

Where a is initial value x is time and r is growth rate

Given function can be written in following form

`f(x)=2500(1+0.75)^(x)` ------------ (2)

After comparing (1) and (2) we can conclude that

`r=0.75 = 75`%