Factor completely 2c^5 + 44c^4 + 242c^3

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John Pitts · Answer 1 · 2017-03-17T14:14:16+0000

2c^5 + 44c^4 + 242c^3
Take 2 c^3 common:
2 c^3 (c^2 + 22 c + 121)
Factorize the quadratic part:
2 c^3 (c^2 + 22 c + 121)
2 c^3 (c+11)(c+11)
Answer

Robert Wills · Answer 2 · 2017-03-19T19:49:39+0000

2c^5 + 44c^4 + 242c^3

Take out common factors.

= 2c^3(c^2 + 22c + 121)

( Refer for attachment for next step )

= 2c^3(c + 11)(c + 11)

= 2c^3(c + 11)^2

Factor completely 2c^5 + 44c^4 + 242c^3-example-1

Factor completely 2c^5 + 44c^4 + 242c^3

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