The half life of radon is 3.80days what would be its decay constant

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asked May 25, 2017 14.6k views

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Andrew Sutton · Answer 1 · 2017-05-31T07:59:55+0000

Half life formula is, 0.5=ek∗t where, k=decay constant t=time substitute time, we get 0.5=ek∗3.80 taking natural logarithm on both sides, we get, ln(0.5)=k∗3.80 or, ln(0.5)/3.80=k k=0.182(ANSWER)

The half life of radon is 3.80days what would be its decay constant

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