Question

May someone help me with this question please anyone please

Answer 1

`5;\ 5;\ 5;\ 5;\ 7;\ 9\\\\\overline{x}=(5+5+5+5+7+9)/(6)=(36)/(6)=6\\\\\delta^2=\frac{(x_1-\overline{x})^2+(x_2-\overline{x})^2+(x_3-\overline{x})^2+...+(x_n-\overline{x})^2}{n}\\\\\delta^2=((5-6)^2+(5-6)^2+(5-6)^2+(5-6)^2+)/(6)`

`(+(7-6)^2+(9-6)^2)/(6)\\\\\delta^2=((-1)^2+(-1)^2+(-1)^2+(-1)^2+1^2+3^2)/(6)=(14)/(6)=(7)/(3)`


`standard\ deviation:\\\\√(\delta^2)=\sqrt{(7)/(3)}=(\sqrt7)/(\sqrt3)=(\sqrt7\cdot\sqrt3)/(\sqrt3\cdot\sqrt3)=\boxed{(√(21))/(3)}\approx\boxed{1.53}`