Question

Simplify the expression the root of negative sixteen all over the quantity of three minus three i plus the quantity of one minus two i..

Answer 1

The first step is to multiply the fraction by (3 +3i) / (3 +3i) to delete the i terms from the denominator:


`( √(-16) )/(3-3i) . (3+31)/(3+3i) +1-2i= (4i(3+3i))/(9+9) +1-2i= (12i-12)/(18) +1-2i=`


`(12i-12+18-36i)/(18) = (6-24i)/(18) = (1)/(3) - (4)/(3) i`