Question

what is the equation of the line that passes through (-3, -1) and has a slope of 3/5 ? put your answer in slope-intercept form.

Answer 1

`The\ slope-point\ form:y-y_1=m(x-x_1)\\The\ slope-intercept\ form:y=mx+b\\--------------------\\m=(3)/(5);\ (-3;-1)\to x_1=-3\ and\ y_1=-1\\\\y-(-1)=(3)/(5)(x-(-3))\\y+1=(3)/(5)(x+3)\\y+1=(3)/(5)x+(9)/(5)\ \ \ \ |subtract\ 1=(5)/(5)\ from\ both\ sides\\\\\boxed{y=(3)/(5)x+(4)/(5)}`