A photon has an energy of 2.93 × 10 to the power of -25 J. What is its frequency? What type of electromagnetic radiation is this photon?

Question

asked Mar 27, 2015 220k views

1 Answer

ConnectedSystems · Answer 1 · 2015-04-01T01:02:08+0000

Answer: The radiation has a frequency of
and is a type of radio wave.

Step-by-step explanation:

The equation given by Planck's follows:

$E=h\\u$

where,

E = energy of the light =
2.93* 10^(-25)J

h = Planck's constant =
6.62* 10^(-34)Js

$\\u$ = frequency of light = ?

Putting values in above equation, we get:

$2.93* 10^(-25)J=6.62* 10^(-34)Js* \\u\\\\\\u=(2.93* 10^(-25)J)/(6.62* 10^(-34Js))=4.43* 10^(9)Hz$

The relation between frequency and wavelength is given as:

$\\u=(c)/(\lambda)$

where,

c = the speed of light =
3* 10^8m/s

$\\u$ = frequency of radiation =
4.43* 10^(8)s^(-1)

$\lambda$ = wavelength of the radiation = ?

Putting values in above equation, we get:

$4.43* 10^(8)s^(-1)=(3* 10^8m/s)/(\lambda)\\\\\lambda=(3* 10^8m/s)/(4.43* 10^8)s^(-1)}=0.677m$

The radiation having wavelength 0.677 m belongs to radio waves.

Hence, the radiation has a frequency of
and is a type of radio wave.