Question

What is the equation of the line, in slope-intercept form, that contains the points (−1, 4) and (2, −5)?

Answer 1

`The\ slope-point\ form:y-y_1=m(x-x_1)\\\\m=(y_2-y_1)/(x_2-x_1)\\\\The\ slope-intercept\ form:y=mx+b\\--------------------\\(-1;\ 4)\to x_1=-1\ and\ y_1=4\\(2;-5)\to x_2=2\ and\ y_2=-5\\\\m=(-5-4)/(2-(-1))=(-9)/(3)=-3\\\\y-4=-3(x-(-1))\\y-4=-3x-3\\\\\boxed{y=-3x+1}`