Question

If an object is projected upward with an initial velocity of 124124 ft per​ sec, its height h after t seconds is h equals negative 16 t squared plus 124 th=−16t2+124t. Find the height of the object after 44 seconds.

Answer 1

The object goes up, reaches its maximum height, goes down, and hits the ground 7.75 seconds after being projected. If nobody steals it, it's still there when t=44 sec.