Question

What is the value of 1/3 x^2 + 5.2y when x = 3 and y = 2?

PLZ HELP!!!

Answer 1

The first step in solving this is to substitute x with 3 and y with 2, so that

`(1)/(3) x^(2) +5.2y`
becomes

`(1)/(3) (3)^(2) +5.2(2)`
Then simply solve using the order of operations.
First exponents (there are no parentheses)

`(1)/(3) 9 +5.2(2)`
Then multiply and divide

`3+10.4`
And finally add and subtract

`13.4`
Therefore the value of 1/3 x^2 + 5.2y when x=3 and y=2 is 13.4