asked 159k views
0 votes
ΔABC is rotated 100° counterclockwise about point P to create ΔA′B′C′. What is m∠C'A'B' ?

2 Answers

3 votes
I believe the answer is 70! :) hope it's right!
answered
User Tentimes
by
8.9k points
3 votes
Base on my calculation and also by the sue of the data you give where as the  triangle ABC is rotated by 100 counter clockwise about point P to create triangle A'B'C' the possible value of angle C'A'B is 70 degrees. I hope you are satisfied with my answer and feel free to ask for more 
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