Question

Consider an assembly line with 20 stations. Each station has a 0.5% probability of making a defect. At the end of the line, an inspection step singles out the defective units. The inspection step catches 80% of all defects. From inspection, units that are deemed to be non defective are moved to the shipping department. Q:What is the liklihood that a unit ends up in a rework?

Answer 1

The likelihood that a unit ends up in rework can be calculated by multiplying the probability of a unit being defective and the probability that a defective unit is not caught in the inspection step.

Step-by-step explanation:

The likelihood that a unit ends up in rework can be calculated by multiplying the probability of a unit being defective and the probability that a defective unit is not caught in the inspection step.

Probability of a unit being defective = 0.5% = 0.005

Probability that a defective unit is not caught in inspection = 1 - 0.8 = 0.2

Therefore, the likelihood that a unit ends up in rework is:

0.005 * 0.2 = 0.001

Answer 2

The answer is 0.4%. The probability that a unit end in a rework can be calculated using the following equation:

P(rework)= P(defects found) * P(defect)
= .8 * .005
= .004
= 0.4%

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