Question

Solve : 6sin^2(x)+2sin^2(2x)=5

Answer 1

6sin2(x)+2sin2(2x)=5-----------------------------

3(1−cos(2x))+(1−cos(4x))=53cos(2x)+cos(4x)+1=03cos(2x)+(2cos2(2x)−1)+1=02cos2(2x)+3cos(2x)=0cos(2x)(cos(2x)+32)=0

Answer 2

After solving the given equation, I’ve come up with the answer cos(2x) (cos(2x) +
`(3)/(2)`) = 0

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