asked 54.9k views
1 vote
From a boat on the lake, the angle of elevation to the top of a cliff is 27°57'. If the base of the cliff is 128 feet from the boat, how high is the cliff (to the nearest foot)?

asked
User Wonderer
by
8.4k points

2 Answers

0 votes

Answer:

Height of cliff = 67.92 ft

Explanation:

Refer the figure given

Distance to base of cliff from boat = AB = 128 feet

Angle of elevation to the top of a cliff = ∠ABC = 27°57'

We need to find height of cliff = AC

We have


tan(27^057')=(AC)/(AB)=(AC)/(128)\\\\AC=67.92ft

Height of cliff = 67.92 ft

From a boat on the lake, the angle of elevation to the top of a cliff is 27°57'. If-example-1
answered
User Frostrock
by
8.1k points
3 votes

If the base of the cliff is 128 feet from the boat, the cliff is 68 feet high. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

answered
User Gowtham
by
8.3k points
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