Question

The annual salaries of all employees at a financial company are normally distributed with a mean of $34,000 and a standard deviation of $4,000. what is the z-score of a company employee who makes an annual salary of $54,000?

–5
–3
4
5

Answer 1

`z=(X-\mu)/(\sigma)=(54000-34000)/(4000)=5`

Answer 2

z-score = 5

Explanation:

the annual salaries of all employees at a financial company are normally distributed with a mean of $34,000 and a standard deviation of $4,000.

To find z-score we use formula

z=
`(x- mean)/(standard \ deviation)`

annual salary of $54,000, x is 54000

Plug in the values in the formula

z=
`(x- mean)/(standard \ deviation)`

z=
`(54000- 34000)/(4000)=5`