Question

What is the equation of a circle with a center at (4, 0) and a radius of 1?

Answer 1

`The\ equation\ of\ the\ circle:\\\\(x-a)^2+(y-b)^2=r^2\\\\where\ (a;\ b)-center;\ r-radius.\\-------------------\\\\(4;\ 0)\to a=4;\ b=0\\r=1\\\\\boxed{(x-4)^2+(y-0)^2=1^2\to(x-4)^2+y^2=1}`