Question

Determine the field strength, E, experienced by a test charge, q, if a charge of 7.0 × 10-5 coulombs is placed on q and a force of 5.2 N is applied.

Answer 1

formula for feild strength= F/q
q=7.0^10-5 coulombs
F=5.2 N
E=5.2 / 7.0^10-5
E=

Answer 2

E = F/q

= 5.2 N / (7* 10⁻⁵) C

= 7.429 * 10⁴ N/C