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Sec^2(pi/2 - x) [sin^2(x) – sin^4(x)]​

Sec^2(pi/2 - x) [sin^2(x) – sin^4(x)]​
asked 229k views
20 votes
Sec^2(pi/2 - x) [sin^2(x) – sin^4(x)]​

asked
User Misol Goh
by
7.6k points

1 Answer

4 votes

it seems that is wrong.sorry for that.

Sec^2(pi/2 - x) [sin^2(x) – sin^4(x)]​-example-1
answered
User Squis
by
8.4k points
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