asked 174k views
4 votes
Find the maximum or minimum of the following quadratic function: y = -2x2 + 4x - 1

A. -1
B. 0
C. 1
D. 4

asked
User EddyG
by
8.4k points

2 Answers

2 votes
all of the above sounds about right ;-;
4 votes
Maximum or minimum value for a quadratic function:

y = -2x² + 4x - 1, a = -2, b = 4, c = -1

y
_(min or max) = (4ac - b²)/4a

= (4*(-2)(-1) - 4²) / 4*(-2)

= (8 - 16) /-8 = -8/-8 = 1.

Since the value it positive, it is a maximum.

C. 1

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