Question

Ethyl acetate reacts with H2, in the presence of a catalyst to yield ethyl alcohol: C4H8O2 + 2H2--> 2C2H6O. A. How many grams of ethyl alcohol are produced by reaction of 2.7 mol of ethyl acetate with H2? B. How many grams of ethyl alcohol are produced by reaction of 13.0g of ethyl acetate with H2? C. How many grams of H2 are needed to react with 13.0g of ethyl acetate?

Answer 1

The balanced chemical reaction is:

C4H8O2 + 2H2--> 2C2H6O

A. How many grams of ethyl alcohol are produced by reaction of 2.7 mol of ethyl acetate with H2? 2.7 mol C4H8O2 ( 2 mol C2H6O / 1 mol C4H8O2) (46.07 g / 1 mol) = 248.78 g ethyl alcohol

B. How many grams of ethyl alcohol are produced by reaction of 13.0g of ethyl acetate with H2?
13.0 g C4H8O2 ( 1 mol / 88.11 g) ( 2 mol C2H6O / 1 mol C4H8O2) (46.07 g / 1 mol) = 13.59 g ethyl alcohol

C. How many grams of H2 are needed to react with 13.0g of ethyl acetate?
13.0 g C4H8O2 ( 1 mol / 88.11 g) ( 2 mol H2 / 1 mol C4H8O2) (2.02 g / 1 mol) = 0.5961 g H2