What are the solution(s) to the quadratic equation 50 – x2 = 0? x = ±2 x = ±6 x = ±5 no real solution

Question

asked Mar 24, 2017 164k views

2 Answers

Rjf · Answer 1 · 2017-03-29T17:58:48+0000

Consider the given quadratic equation
50-x^2=0

x^2-50=0

Comparing the given quadratic equation to the general equation
ax^2+bx+c=0 , we get a= 1, b=0 and c= -50

So, the solution to the quadratic equation is given by:

$x = (-b \pm √(b^2-4ac))/(2a)$

$x = (-0 \pm √(0^2-4(1)(-50)))/(2)$

$x = (\pm √(200))/(2)$

$x = \pm \sqrt2 (5)$

$x = \pm 5\sqrt2$

So, the solutions to the given quadratic equation are
$x = \pm 5\sqrt2$ .