Question

What is the theoretical yield of Fe2(SO4)3 if 20.00 g of FePO4 reacts with an excess of Na2SO4?

Answer 1

A. 26.52g

got it right :)

Answer 2

The balanced chemical reaction is:

FePO4 + Na2SO4 = Fe2(SO4)3 + Na3PO4

We are given the amount of FePO4 is given to be used in this reaction. This will be the starting point for the calculations.

20.0 g FePO4 ( 1 mol FePO4/ 150.82 g FePO4 ) ( 1 mol Fe2(SO4)3 / 1 mol FePO4) ( 399.88 g Fe2(SO4)3/ 1 mol Fe2(SO4)3) = 53.0274 g Fe2(SO4)3