Question 3 . amaths really need help. calculus. reply quicky thanks

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The Godfather · Answer 1 · 2017-05-30T23:45:17+0000

Hello,

1)
y=(2x-7)(x+5)^3

y'=2(x+5)^3+(2x-7)*3*(x+5)²
if x=4 then
y'=2*9^3+1*3*9²=1701

2)
y=(3x-2)/√(x+2)

y'=(3*√x+2 - (3x-2)/(2*√x+2))/(x+2)