Question

The equation of a line that passes through point (7,3) and is parallel to y=2\7x-3

Answer 1

The general form of the equation is:
y = mx + b
We know that the slope m of the required line is 2/7, the reason being that the two lines must be parallel and therefore must have the same slope.
We can now write an interim equation:

`y=(2)/(7)x+b`
When the values of the given point, x=7 and y=3, are plugged into the interim equation we get:
3 = 2 + b
Therefore b = 1, and the required equation is:

`y=(2)/(7)x+1`