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-3y(-4y)=32+(x^0+y^0)^5

-3y(-4y)=32+(x^0+y^0)^5
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-3y(-4y)=32+(x^0+y^0)^5

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User Mushfiq
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1 Answer

3 votes
Any number to the power of 0 equals 1. So, we can rewrite the equation as follows:

12y=32+2^(5)=32+32=64

y=(64)/(12)=5(1)/(3)
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User Haxney
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