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Please help. (1/x)<2. It says to concider 2 cases. I already got x>(1/2). How do I find another case.

Please help. (1/x)<2. It says to concider 2 cases. I already got x>(1/2). How do I find another case.
asked 97.8k views
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Please help. (1/x)<2. It says to concider 2 cases. I already got x>(1/2). How do I find another case.

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User Nirav Bhatt
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8.2k points

1 Answer

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(1)/(x)<2|\cdot x^2\\ x<2x^2\\ 2x^2-x>0\\ x(2x-1)>0\\ x\in(-\infty,0)\cup((1)/(2),\infty)
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User Narko
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