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What is the equation of the line, in slope-intercept form, that passes through (4, 2) and (-2, -3)? 5x - 6y - 8 = 0 3y = -2x + 20 y = x - 5/6 x -4/3

What is the equation of the line, in slope-intercept form, that passes through (4, 2) and (-2, -3)? 5x - 6y - 8 = 0 3y = -2x + 20 y = x - 5/6 x -4/3
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What is the equation of the line, in slope-intercept form, that passes through (4, 2) and (-2, -3)? 5x - 6y - 8 = 0 3y = -2x + 20 y = x - 5/6 x -4/3

asked
User JWD
by
8.6k points

1 Answer

7 votes
The gradient is 5/6 so if this is plugged into an equation along with one of the points.

y - b = m(X-a)
y - 2 = 5/6 (X-4)
6y - 12 = 5 (X-4)
6y - 12 = 5x - 20
6y - 5x - 8 = 0
answered
User Leonardo Costa
by
8.2k points
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